Plz help me with this, plz?

Question

Im lost!!! percent weight of the acid...?
Given that the molar mass of Vinegar is 60.0g and that the density of the vinegar solution is 1.01 g/ml, calculate the percent weight of the acid in the sample.

Additional Details

1 hour ago
Moles of Vinegar= 0.0034 moles
Molarity of Vinegar= 0.68


This the other info I have :(

molar mass of vinegar= 60.0g

Answer 1

Okay:

% weight of acid = weight of acid/ total weight of solution *100

Need to now the weight of Vinegar.
From moles = mass/MW
mass = moles * MW
= 0.0034*60
=0.204g

Now we need the weight of the solution
Molarity = moles/vol
Vol= moles/molarity
= 0.0034/0.68
=0.0050 litres
= 5ml

Need to convert to grams
Density= mass/vol
mass = density*vol
=1.01*5
=5.05g

Putting these figures back into the first equation
% w/w vinegar = 0.204/5.05*100
=4.04%

NOTE:
JUST DID CORRECTION INITIAL ANSWER OUT BY FACTOR OF TEN

Answer 2

Mass of soln. ???