Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it.?

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limx--->inf. (3x)/(ln(5+4e^x)) = ?

I've so many ways...but none of them worked.

2007-04-23 19:08:45 · 2 answers · asked by ... 1 in Science & Mathematics ➔ Mathematics

l'Hop works great!

lim x=>oo 3 / [4e^x/(5+4e^x)]
lim x =>oo 3(5+4e^x) / 4e^x
= 3

2007-04-23 19:13:53 · answer #1 · answered by Anonymous · 0⤊ 0⤋

= lim 3/ 4e^x/(5+4e^x)
= lim 3(5+4e^x)/4e^x
= lim 3(5/4e^x +1)
= 3(0+1) =3 as x --> infinity

2007-04-24 02:24:14 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋