ugggh chem help!?

Question

i dont want the answer, so again, i just need the steps...sorry this is my second question i know it must be annoying but here it goes:

*i have a balanced chemical reaction

*i have the amount of each of the two reactants (in grams)

*there are two products

*i need to know how much of each product is produced

im sorry i cant give numbers cause id like to figure it out with just the steps!!! thank you soo much.

Answer 1

Think of the following:
(grams to moles: moles to moles: moles to grams)
If you have GRAMS of reactants, you must convert them to moles by dividing by their MOL WEIGHT.

Use the reaction to determine the number of MOLES of product formed from 1 MOLE of a reactant. Then, with the moles you have, determine the number of moles of product.

Once you have the moles of product, MULTIPLY that by the product's mole weight to get grams.

The whole key to the stoichiometry mess is to realize that you have to go to the reaction before you can figure out weights of products.

Answer 2

Suppose your reaction looks like
AW + BX → CY + DZ
where A,B,C and D are the balancing numbers and W,X,Y and Z are the chemicals.
Let a = grams of W and b = grams of X.
Calculate a/A and b/B.
The smaller ration will be the limiting reagent.
If a/A is the smaller ratio,
c/C = d/D = a/A
If b/B is the smaller ratio,
c/C = d/D = b/B

Answer 3

-use molar masses to get the amount of moles of both reactants.
-use a mole to mole ratio of both reactants to a product to figure out which is limiting and which is in excess
-use the limiting reactant for the amount of moles you use
-figure out the molar mass of the products and then solve for grams

useful formula n=m/mm
where n = # mol m = mass and mm = molar mass