Im lost!!! percent weight of the acid...?

Question

Given that the molar mass of Vinegar is 60.0g and that the density of the vinegar solution is 1.01 g/ml, calculate the percent weight of the acid in the sample.

Moles of Vinegar= 0.0034 moles
Molarity of Vinegar= 0.68


This the other info I have :(

Answer 1

Molarity = moles of vinegar / Liters of solution

0.68 = 0.0034 moles of vinegar / # Liters of solution

thus 0.0034 / 0.68 = 0.005 Liters solution of vinegar

0.005 Liters x 1000 = 5 ml solution of vinegar


5 ml x 1.01 g/ml = 5.05 grams of vinegar solution

0.0034 moles of vinegar x 60.0 g molar mass = 0.204 g vinegar in the sample

Thus the weight % of vinegar in the sample is 0.204 / 5.05 x 100 = 4.04%

Answer 2

So am I. Something is missing.