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to the equivalence point using 0.125 M NaOH. How many milliliters of NaOH will be required to neutralize the acid solution? A.) 61.4 mL B.) 86.0 mL C.)112 mL D.) 123 mL

2007-04-23 17:22:03 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

2x0.215x25/700 mol = 0.037 mol are required

that is contained in 0.037/0.125 = 0.296 L = 29.6 ml

2007-04-23 19:24:26 · answer #1 · answered by ag_iitkgp 7 · 0 0

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