Adding Sin Graphs/Functions? URGENT!!?

Question

Does anyone know about the Superposition of Sinusoids? Do I just add the functions together like this: for example if my two functions were f(x)=sin2x and g(x)=sinx/2...would the superpostion of the graph look like y(x)=sin2x+sinx/2 ? Thanks...

Does anyone know about the Superposition of Sinusoids? Do I just add the functions together like this: for example if my two functions were f(x)=sin2x and g(x)=sinx/2...would the superpostion of the graph look like y(x)=sin2x+sinx/2 ? Thanks...

Okay, here's more information...my two actual equations are:
y=50sin(pi/5)(x-2.5) +160

and

y=100sin(pi/10)(x-5) +200

But all I need to know is the correct way to add these things...not the graph or anything, I know what that looks like...just how to add the function part...thanks soo much if anyone answers!

anyone? i'm really stuck.....

Answer 1

?????????

General Research Guides for Students:

http://www.aresearchguide.com/

http://www.geocities.com/athens/troy/886...

http://www.studentresearcher.com/search/...

http://findarticles.com/

Research Link (type author, title or a key word or 2 into the search engine and fingers crossed.)

Answer 2

a TOTAL stranger? sorry, but yeah. that's just a little too...creepy. we're not in 4th grade playing tag anymore. anyone whose had an account suspended or collected a pile of VNs knows it's sinful NOT to be wary. if a stranger adds you and they don't email you first, email them back explaining that you would like to know what it was you asked or answered that they were interested in. if they don't allow email, that's just rude and asking to be blocked.

Answer 3

You do add the functions sinA + sinB, but you can simplify by using the trig identities. In your given functions, you can multiply out the arguments in the sin functions:

sin[π/5 * (x-2.5)] = sin(πx/5 - π/2)
sin[π/10 * (x-5)] = sin(πx/10 - π/2)

sin[A - π/2] = -cosA

That will simplify your addition

Answer 4

sin[π/5 * (x-2.5)] = sin(πx/5 - π/2)
sin[π/10 * (x-5)] = sin(πx/10 - π/2)
sin[A - π/2] = -cosA

Answer 5

no clue darlin