Hi, I've just been given this assignment in physics to create a set of notes explaining the relationship of Millikan's Oil Drop experiment with magnetism. I know that the experiment was initially used to find the charge of an electron as well as its mass. I also know that the Oil Drop Experiment has a huge relationship to electrostatics. What I'm confused about is how it relates to magnetism. Can any of you possibly elaborate or clarify this with possible diagrams and equations and explanations?
2007-04-23 14:43:41 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
It's an electrostatic field that supports the droplet against the gravitational field, not a magnetic field. The charge doesn't move when equilibrium is reached, so there's no magnetic field at all in the problem.
2007-04-23 16:01:22 · answer #1 · answered by Dr. R 7 · 0⤊ 0⤋
When the downward force of gravity on the drop was equal to the upward magnetic force, the two forces were balanced and you could determine the charge of the drop.
So, you'd have a positive plate at the top, accelerate the electron down, and notice exactly where the electron stopped with respect to the ground.
2007-04-23 14:47:23 · answer #2 · answered by Sci Fi Insomniac 6 · 0⤊ 0⤋
Keep in mind that any charged object (here an oil drop) having a movement create a magnetic field.
Movement, electricity and magnetism are always linked.
2007-04-23 14:52:25 · answer #3 · answered by Plain truth 3 · 0⤊ 0⤋
it incredibly is back..... i know how risky IS a splash getting to understand .... that's the two upward and downward...as in step with standards of the test to maintain the oil-drop table certain. while it falls below gravity, the upward field counter balances the stream and while it incredibly is upwrd, the downward field (by way of utilising utilising a change interior the circuit) comes into play. think of!
2016-11-27 00:01:44 · answer #4 · answered by ? 4 · 0⤊ 0⤋