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First convert the pH to a [H+]. That will also equal the benzoate ion concentration. Then, substitute those into the expression for Ka and solve for the [benzoic acid]. That will give you an answer in moles/L, so multiply that by 0.5 to get the moles to dissolve in 500 mL. Finally, convert the moles into grams with the molar mass of benzoic acid.

2007-04-23 14:44:16 · answer #1 · answered by hcbiochem 7 · 0 0

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