... Use R[sch] = 2GM/c^2
where G = 6.67 x 10^-11 Nm^2/kg^2
and c = 3 x 10^8 m
(and i use 1.99 x 10^30kg for the M (mass)
i got.... 8.85 x 10^12 N/kg
i was wondering if that is right or not..?
2007-04-23 14:31:57 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Astronomy & Space
alright, i just found out that the units for N are...
mkg/s^2
and i've redid the calculation.
my new answer is...
R=2.9496 x 10^3 m
is that right?
2007-04-23 15:15:05 · update #1
First the sun would have to go Super Nova, it would expnad out to mars, and we'd be sucked in,
2007-04-23 14:37:06 · answer #1 · answered by Anonymous · 0⤊ 2⤋
Your formula is right, but you slipped a decimal place and also divided only by c instead of c^2. So, using your (correct) numbers, the calculation is
R = 2 x 6.67e-11 x 2e30/(3e08)^2 = 2964 meters (everything is in MKS units), which is the correct answer.
2007-04-23 15:10:37 · answer #2 · answered by Astronomer1980 3 · 0⤊ 0⤋
The number is way too big and the units are screwed up. The answer should be in meters....
2007-04-23 14:45:34 · answer #3 · answered by Gene 7 · 0⤊ 0⤋
The answer will be in meters...so no your answer is wrong. Use factor/labeling to get the answer in meters. When everything cancels out except meters you have your answer.
2007-04-23 14:42:57 · answer #4 · answered by Perry L 5 · 0⤊ 0⤋
The answer is actually fairly well known but you should try and derive it correctly. If I recall correctly it should be 2.95 km
2007-04-23 14:38:04 · answer #5 · answered by jerryjon02 2 · 0⤊ 0⤋