algebraic equations?

Question

Hey. I'm new to these kind of problems and I was wondering how to figure this out. :
2n-1/3 (in quotations) to the fourth power
multiplied by
9/2n-1 (in quotations) to the second power
????

Answer 1

Hi Chipmunk,

If you have (2n - 1) to the 4th power on top and you have (2n - 1) to the second power on the bottom, you can subtract their exponents, leaving (2x - 1) squared on the top.

If you have 3 to the fourth on the bottom that's 3 x 3 x 3 x 3 = 81 and if you have 9 to the second power on top, that's 9 x 9 = 81. Since they both equal 81, they cancel each other out.

All you have left is (2x - 1)^2

I hope that helps you! :-)

Answer 2

(2n-1/3)^4(9/2n-1)^2
What you really mean, I think, is:
[(2n-1)/3]^4 * [9/(2n-1)]^2
= (2n-1)^4/3^4 * 9^2/(2n-1)^2
= (2n-1)^2
These ( ) are called parentheses and " " are called quotes.
Make sure you use parentheses correctly, or you will create great confusion for the reader.