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lim ((5e^2x-e^-2x) / (4e^2x+3e^-2x))
x->-infinity

limit=
A) -1/3
B) 1/3
C) 3
D) -3
E) -4/7
F) 4/7

2007-04-23 12:02:09 · 2 answers · asked by ph103 1 in Science & Mathematics Mathematics

2 answers

lim ((5e^2x - e^-2x)/(4e^2x + 3e^-2x)) = lim (-e^-2x)/(3e^-2x) =
= -1/3

Because e^2x tends to zero as x approaches -inf.

2007-04-23 12:11:02 · answer #1 · answered by Amit Y 5 · 0 0

The answer is A)

2007-04-23 19:05:48 · answer #2 · answered by dodgetruckguy75 7 · 0 0

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