Calculus:Volumes?

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The base of a certain solid is the area of y=f(x)=9 and below by the graph of y=g(x)= 16 x^2. Cross-sections perpendicular to the x-axis are squares. Find the volume.

2007-04-23 11:46:16 · 1 answers · asked by bhicks 1 in Science & Mathematics ➔ Mathematics

1 answers

V = ∫(9 - 16x^2)^2dx from 0 to 3/4
V = ∫(81 - 288x^2 + 256x^4)dx from 0 to 3/4
V = [81x - 96x^3 + (256/5)x^5] from 0 to 3/4
V = 81(3/4) - 96(27/64) + (256/5)(243/1024) - 0

2007-04-23 13:26:02 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋