What is the equation of the line containing (0,3) and (2,11), in slope intercept form?

Answer 1

Slope:
m=(y2-y1)/(x2-x1)
m=(11-3)/(2-0)
m=8/2=4

Slope-intercept form:
y-y1=m(x-x1)
y-3=4(x-0)
y-3=4x
y=4x+3

Answer 2

First calculate the slope of the line.

m = ∆y/∆x = (11 - 3)/(2 - 0) = 8/2 = 4

The slope intercept form of of a line with slope m and containing the point (h,k) is:

y - k = m(x - h)

For the question at hand pick one of the points. Let's use the first one (0,3).

y - 3 = 4(x - 0)
y - 3 = 4x

Answer 3

The slope of this line is 8/2 or 4

The y-intercept is at (0, 3) .. or 3

The equation y = mx + b

is y = 4x + 3