I need it to be factored!
Again, that's
(k+8)^2 - 1.
Thank you!
2007-04-23 07:35:27 · 9 answers · asked by Hollie 3 in Science & Mathematics ➔ Mathematics
step1. apply FOIL to simplify and convert to QUADRATIC equation ..
(k + 8 ) ( k + 8) = k^2 + 8k + 8k + 64
step2 given expression become .
k^2 + 16k + 64 - 1
k^2 + 16k + 63
step3 factorise constant term 63 in such way that sum of factors is equal to coefficient of middle term (16)
we get 9 x 7 = 63 and 9 + 7 = 16
apply FLIP the FOIL method ...
(k + 9)( k + 7)
2007-04-23 07:39:07 · answer #1 · answered by RAKESHtutor 3 · 0⤊ 0⤋
If you want to expand it, it' s k^2+16k-64-1
= k^2+16k+63.
If you want to factor it as the difference of 2
squares it' s (k+8+1)(k+8-1) = (k+7)(k+9).
2007-04-23 15:07:53 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
(k+8)^2 - 1
=K^2 +16K+ 64 -1
=k^2 +16k +63
=(k + 9)(k + 7)
2007-04-23 14:43:47 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(k^2 + 16k + 64 - 1 )
k^2 + 16k + 63
now you factor it
(k + 9)(k+7)
k= -9, -7
2007-04-23 14:44:37 · answer #4 · answered by mc 2 · 0⤊ 0⤋
= k² + 16k + 64 - 1
= k² + 16k + 63
= (k + 9).(k + 7)
2007-04-23 14:39:46 · answer #5 · answered by Como 7 · 0⤊ 0⤋
k^2 + 16k + 63
2007-04-23 14:38:35 · answer #6 · answered by mkveliferrari 2 · 0⤊ 0⤋
k^2 +16k + 64 - 1
k^2 +16k +63
(k+9) (k+7)
k=-9
k=-7
HOPE THAT HELPS =)
2007-04-23 14:45:41 · answer #7 · answered by xoxbritz36xox 2 · 0⤊ 0⤋
k²+16k+63
(k+7)(k+9)
2007-04-23 14:40:00 · answer #8 · answered by Anonymous · 0⤊ 0⤋
(k+8)^2-1
k^2+16k+64-1
k^2+16k+63
(k+7)(k+9)
k=-7
k=-9
2007-04-23 14:41:14 · answer #9 · answered by Astral Walker 7 · 0⤊ 0⤋