2007-04-23 07:18:48 · 8 answers · asked by dawoud a 1 in Science & Mathematics ➔ Mathematics
cos(90°-x) = sin(x)
sin(x+45°) = cos(90°-[x+45°]) = cos(45°-x)
So they're the same.
Cos(45°-x) = 0.9659
2007-04-23 07:24:47 · answer #1 · answered by Anonymous · 1⤊ 0⤋
As x + 45 deg and 45 - x deg add up to 90 deg, cos(45 - x)= sin(x + 45) = 0.9659.
2007-04-23 14:23:50 · answer #2 · answered by Anonymous · 1⤊ 0⤋
cos(45-x) = sin(90 -(45 - x)) = sin(x = 45) = 0.9659
2007-04-23 14:29:29 · answer #3 · answered by Steiner 7 · 1⤊ 0⤋
cos(90- theta )= sin theta
substitute theta=45+x then , 90 - theta=90-45-x=45-x,
therefore cos(45-x)=cos{90-(45+x)}=sin (45+x)=0.9659
2007-04-23 14:29:57 · answer #4 · answered by ukmudgal 6 · 1⤊ 0⤋
It's the same thing because cos(90-x) = sin(x)
So sin(x+45) = cos(90-x-45) = cos(45-x)
2007-04-23 14:26:03 · answer #5 · answered by Dr D 7 · 0⤊ 1⤋
sin (x + 45)
= sin x cos 45 + cos x sin 45
= (sin x)(sqrt 2 / 2) + (cos x)(sqrt 2/2)
= (sqrt 2 / 2)(sin x + cos x)
cos (45 - x)
= cos 45 cos x + sin 45 sin x
= (sqrt 2 / 2)(cos x) + (sqrt 2 / 2)(sin x)
= (sqrt 2 / 2)(cos x + sin x)
So...
sin (x + 45) = cos (45 - x) = 0.9659
2007-04-23 14:24:22 · answer #6 · answered by Mathematica 7 · 0⤊ 1⤋
cos(45-x)=sin(90-(45+x))=sin(x+45)=0.9659
2007-04-23 14:34:43 · answer #7 · answered by Tommy 2 · 0⤊ 0⤋
Also .9659.
2007-04-23 14:24:08 · answer #8 · answered by Mark 6 · 0⤊ 1⤋