One person hits the rail with a hammer, while another one is some distance away with one ear on the rail. Suppose that the time difference between the arrivals of the two sounds travelling through air and through steel is 3.62 s. If the speed of sound in air was 338.6 m/s, how far (in km) are the two persons apart?
For steel, Young's modulus is 2.0 · 1011 N/m2 and the density is 7800 kg/m3.
2007-04-23 07:08:46 · 5 answers · asked by Division12 2 in Science & Mathematics ➔ Physics
Vs=SQRT(2.0*1011 N/M2 / 7800 kg/M3)
Vs=SQRT(25 641 026)
Vs=5063.697 m/s through steel
Va=338.6 m/s through air
If "d" is the distance between the 2 guys
(d / Vs) +3.62 = d / Va
d*Va + 3.62*Va*Vs = d*Vs
3.62*Va*Vs = d*Vs - d*Va
3.62 * 338.6 *5063.697 = 5063.697d - 338.6d
6206735.451204 = 4725.097d
1313.5678381... = d in meters
d = 1.3 km
2007-04-23 07:44:41 · answer #1 · answered by Dr Strangelove 2 · 0⤊ 0⤋
If the time b/n 2 chirps is 7x10^-2 s then the frequency of the sound wave is inverse of the term, i.e., f= a hundred/7 s-a million. If the whole meditated wave has to attain the bat it must be at-least one unit wavelength far off from the article. consequently, WaveLenght = velocity/ Frequency, and right here velocity of sound is 3x10^8 m/s. Wavelenght = 3x10^8 x7 / a hundred = 21 x 10^6 m or the utmost distance the article may well be away is two.a million x 10^7 m
2016-10-13 07:05:55 · answer #2 · answered by ? 4 · 0⤊ 0⤋
speed = distance/time
The faster which a sound wave travels, the more distance it will cover in the same period of time. If a sound wave is observed to travel a distance of 700 meters in 2 seconds, then the speed of the wave would be 350 m/s. A slower wave would cover less distance - perhaps 600 meters - in the same time period of 2 seconds and thus have a speed of 300 m/s. Faster waves cover more distance in the same period of time.
it takes the second hand of a clock 60 seconds to move around one time
- if it goes one-quarter turn, it takes 1/4 times 60 seconds, or 15 seconds
- remember that each complete rotation of the disk takes about 1/50 s; so for one-quarter turn, it takes about (1/4) x (1/50 s) = 1/200 s
- we can see now that it takes sound about 1/200 s to travel about 1.7 meters, or about one adult armspan
- so when I hold my arms apart and snap the fingers of one hand, it takes the sound 1/200 s to reach the other hand
- if the sound traveled 1.7 m in 1/200 s, how far would it travel in 1 s? 200 times as far or 1.7 m x 200 = 340 m, so the the speed of sound is 340 meters per second
2007-04-23 07:22:07 · answer #3 · answered by Anonymous · 0⤊ 1⤋
c(a) = 338.6 m/s
c(s) = √((2.0*10^11 N/m2)/(7800 kg/m3))
c(s) = 5063.697 m/s
d/338.6 - d/5063.697 = 3.62 s
(5063.697 - 338.6)d = 3.62*5063.697*338.6
d = 1,313.568 km
2007-04-23 07:45:36 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
Mach one
2007-04-23 07:16:59 · answer #5 · answered by Palerider II 2 · 0⤊ 1⤋