the y-intercept is -4
the x-intercept is 6
2007-04-23 07:02:47
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answer #1
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answered by Anonymous
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When x=0 then y=-4 and when y=0 x=6
2007-04-23 14:04:25
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answer #2
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answered by dwinbaycity 5
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y intercept (x = 0) : -3y - 12 = 0 => y = -4
x intercept (y=0) : 2x = 12 => x = 6
2007-04-23 14:07:19
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answer #3
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answered by Anonymous
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plug in x=0 to solve for the y-intercept: 2(0)-3y-12=0
-3y-12=0 .. solve for y. The y-intercept will be (0, y) where y is the value you solved for.
plug in y=0 to solve for the x-intercept: 2x-3(0)-12=0
2x-12=0 .. solve for x. The x-intercept will be (x,0) where x is the value you solved for.
2007-04-23 14:07:04
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answer #4
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answered by slik 2
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2x - 3y - 12 = 0
When determining the intercepts, you let one of the variables be equal to zero. For the x-intercept, let y = 0, and for the y-intercept let x = 0.
2x - 3(0) - 12 = 0
2x - 12 = 0
2x = 12
x = 6
2(0) - 3y - 12 = 0
-3y - 12 = 0
-3y = 12
y = -4
So the coordinate points would be: (6,0) and (0, -4)
2007-04-23 14:05:17
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answer #5
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answered by skm4usa 3
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to plug in intercepts, u plug in 0- for example, if ur trying to find x, u plug in 0 for y
REMEMBER: anything times 0 is 0
2x-3(0)-12=0
2x-0-12=0
2x-12=0
2x=12
x=6
2(0)-3y-12=0
0-3y-12=0
-3y-12=0
-3y=12
y=-4
2007-04-23 14:04:33
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answer #6
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answered by mary 1
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When y = 0:-
2x = 12
x = 6
When x = 0:-
- 3y = 12
y = - 4
Intercepts are (6,0) and (0,- 4)
2007-04-23 14:04:41
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answer #7
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answered by Como 7
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I think it is 6 for x and - 4 for y, but i am a little rusty on my algebra
2007-04-23 14:02:58
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answer #8
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answered by the_end_of_the_cons 5
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