Solve the equation...?

Question

x2 + 4x - 10 = 0
2 in equation above means squared
Help solve it please!

Answer 1

It doesn't factor, so you need to use the quadratic formula...

a = 1
b = 4
c = -10

x = [1/(2a)][-b +- sqrt (b^2 - 4ac)]
x = [1/(2*1)][-4 +- sqrt (4^2 - 4*1*-10)]
x = (1/2)[-4 +- sqrt (16 + 40)]
x = (1/2)(-4 +- sqrt 56)
x = (1/2)(-4 +- sqrt (4*14))
x = (1/2)(-4 +- 2 sqrt 14)
x = -2 +- sqrt 14

or, for an approximate answer...
x = -2 +- 3.7417
x = -5.7417 and 1.7417

Answer 2

If you find it hard to remeber the formula that everyone is quoting then try:

Rearrange it to
x2 + 4x + 4 - 14 = 0 The second 4 comes from the dividing the coefficient of x by 2 and squaring it, the -14 adjusts this number back to -10

(x + 2)^2 - 14 = 0 by "completing the square"

(x + 2)^2 = 14

(x + 2) = + or - square root 14

x = - 2 + or - square root 14

and so on

Answer 3

You'll find that this doesn't fact, so you'll have to resort to either completing the square or the quadratic formula. To use completing the square:

x^2 + 4x - 10 = 0
x^2 + 4x = 10
x^2 + 4x + 4 = 14
(x + 2)^2 = 14
x + 2 = ±√14
x = -2±√14

To use the somewhat messier quadratic formula:
x = [-b ± √(b² - 4ac) ] /2a
x = [ -4 ± √(16 - 4(-10) ] / 2
x = [ -4 ± √56 ] / 2
x = [ -4 ± √4*14 ] / 2
x = [ -4 ± 2√14 ] / 2
x = -2 ± √14

Answer 4

x2+4x-10=0 ==> x2+4x+4=14 ==> (x+2)^2=14 ==> x+2=sqrt(14)=14^0.5 ==> x=-2+sqrt(14) Or x=-2-sqrt(14)
what age are u in?

Answer 5

x² + 4x - 10 = 0

Factorise LHS

(x ....... )(x........) = 0

There are no factors of ten that give a sum/difference of four

SO We need the Formula:-

x = [-b ± √(b² - 4ac)]/2a {Where a = 1 ; b = 4 and c = -10}

x = [ -4 ± √( 16 - {4 x -10}] / 2

Calculate

x = [ -4 ± √56] / 2

x = [ - 4 ± 7.49] / 2

x = [ - 11.49 / 2] OR [ 3.49 / 2]

x = - 5.74 OR x = 1.74

Answer 6

start with the substitution for (x^2 + 4x)
(x + 2)^2 = x^2 + 4x + 4

then plug in the substitution and balance the numerals
(x + 2)^2 = 14

then take the root of each side
x +2 = +/- sqrt(14)

and solve
x = -2 +/- sqrt(14)

Answer 7

there are two ways in doing this question but i will tell you the 'completing the square' method:
[(x+2)^2] -4-10=0
i got the 2 in the brackets from halving the 4 and got the 4 from 2^2 (2 squared)
so [(x+2)^2] -14 = 0
(x+2)^2=14
x+2=(+/- square root of 14)
x= (+/- square root of 14) -2
thats it you get two answers one is with positive square root the other is with a negative square root

Answer 8

x2 + 4x + 4 - 4 - 10 = 0
(x + 2)^2 - 14 = 0
(x + 2 + sqrt14)(x + 2 - sqrt14) = 0
x = - 2 - sqrt14
x = -2 + sqrt14

Answer 9

x^2 + 4x - 10 = 0.

Try the quadratic formula.

Answer 10

Quadratic formula

[-b ± √(b² - 4ac)]/2a

[-4 ± √(16 - (-40))] / 2

[-4 ± √ 56 ]/2

[-4 ± √(4)(14)]/2

-2 ± √14

-2 ± 3.74

x = -5.74 or x = 1.74