2007-04-23 04:51:50 · 7 answers · asked by raul 1 in Science & Mathematics ➔ Mathematics
beause from the 1st series one element is deleted for the 2nd expression we get substituting n+1 for n or
1/2(n+1)(n+2)
2007-04-23 05:01:56 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
1\2*(n+1)(n+2)
2007-05-01 00:52:03 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The nth term for the second series is the (n+1)th for the previous one
So it is 1/2*(n+1)(n+2)
2007-04-23 12:05:35 · answer #3 · answered by Dr D 7 · 0⤊ 0⤋
1/2.(n+1)(n+2).
2007-05-01 06:34:16 · answer #4 · answered by rajendra k 3 · 0⤊ 0⤋
same sequence but 1 term later, so
(n+1)(n+2)/2
2007-04-23 12:02:35 · answer #5 · answered by Philo 7 · 1⤊ 0⤋
this is equal to (n+1)th term of 1,3,36,10,15,21 .........
which is
)1/2(n+1(n+2).answer
2007-05-01 09:47:38 · answer #6 · answered by Anonymous · 0⤊ 0⤋
this is easy...
(n+1)(n+2)/2
2007-05-01 11:21:38 · answer #7 · answered by Anonymous · 0⤊ 0⤋