Same way you did in 5th grade; start by getting common denominators:
1/a + 1/b =
b/(ab) + a/(ab) =
(b+a)/(ab)
2007-04-23 04:52:47
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answer #1
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answered by Philo 7
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1/a + 1/b = (a+b)/a*b
2007-04-23 04:50:43
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answer #2
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answered by SuNiL 3
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Multiply each fraction by 1.
But dont write one, in the traditional way..
For 1/a..Multiply it by 1 written as b/b
For 1/b Multiply it by 1 written as a/a
1b/ab + 1a/ab
Eliminte the one coefficent in the numberator..they are unnecessary
b/ab + a/ab= b+a/ab
2007-04-23 04:53:22
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answer #3
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answered by RScott 3
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cross multiply the denominators to the numerators then add, then multiply the denominators
1/a + 1/b ; (b + a) / ab or (a+b) / ab
2007-04-23 04:53:39
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answer #4
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answered by hacker_lexy 3
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use the definition x/a+y/b =(bx+ay)/ab
b/b*x/a=1*x/a=x/a=bx/ab
2007-04-23 05:11:56
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answer #5
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answered by mathman241 6
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b / ab + a / ab = (b + a) / ab
2007-04-23 04:56:29
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answer #6
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answered by Como 7
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b/ab+a/ab= (b+a)/ab
2007-04-23 04:51:32
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answer #7
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answered by dwinbaycity 5
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