the expression
( - 3 yx^2/x^-2 y^6)^3
is equal to -27 x^12 y^15
2007-04-23 04:16:39 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I'm going to assume the x^-2 y^6 is all under the fraction, so you have:
[ (-3 y x^2 ) / (x^-2 y^6) ]^3 =
[ (-3 y x^4 ) / ( y^6) ]^3 =
[ (-3 x^4 ) / ( y^5) ]^3 =
[ -3 x^4 y^-5 ]^3 =
-27 x^4 y^-15
Close, but no kewpie doll
2007-04-23 04:22:39 · answer #1 · answered by Anonymous · 2⤊ 0⤋
The answer should be
-27 x^(12) y^(-15)
or
-27 x^(12) / y^(15)
2007-04-23 11:22:49 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
The answer is false because the y^15 should be in the denominator.
2007-04-23 11:20:09 · answer #3 · answered by bruinfan 7 · 1⤊ 0⤋
(-3x²y)(x² ) / y^6 = (-3x^4 / y^5)³ = -27x^12 / y^15.
2007-04-23 11:23:41 · answer #4 · answered by S. B. 6 · 0⤊ 0⤋
yeah, its false
the 15 should be negetive (-)
2007-04-23 11:24:49 · answer #5 · answered by absentmindednik 3 · 0⤊ 0⤋
Oh yeah.
2007-04-23 11:19:29 · answer #6 · answered by SALSA 6 · 0⤊ 1⤋