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3x^2+4x-7=

2007-04-23 03:50:38 · 4 answers · asked by JORGYPORGY 1 in Science & Mathematics Mathematics

4 answers

(3x + 7)(x - 1) = 0

x = 1 or -7/3

2007-04-23 03:53:50 · answer #1 · answered by MamaMia © 7 · 0 0

3x^2 + 4x - 7
=3x^2 -3x + 7x - 7
=3x(x-1) + 7(x-1)
=(3x+7)(x-1)

2007-04-23 10:55:54 · answer #2 · answered by gudspeling 7 · 0 0

3x^2+4x-7=0
(3x+7)(x-1)=0
3x+7=0,x-1=0
x=-7/3,x=1

2007-04-23 10:55:37 · answer #3 · answered by py 2 · 0 0

(3x + 7).(x - 1)

2007-04-23 11:00:13 · answer #4 · answered by Como 7 · 0 0

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