Is the square root of 8x^2 just 8x?
2007-04-21 22:35:57 · 10 answers · asked by mbchelsea 1 in Science & Mathematics ➔ Mathematics
No. You have to take the square root of 8, as well as of x^2.
The square root of 8x^2 is:
x sqrt(8)
= x sqrt(4)sqrt(2)
= 2x sqrt(2).
2007-04-21 22:39:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
square root of 8x^2 = 2.83x
2007-04-21 22:40:10 · answer #2 · answered by bach 2 · 0⤊ 0⤋
No
2*(2)^(1/2)*x
i.e
sqrt(8)*x
2007-04-21 22:38:34 · answer #3 · answered by Aswin Kumar 2 · 0⤊ 0⤋
A sq. root is the alternative of the sq. of a great decision. as an occasion, sixteen is 4 squared. So the sq. root of an algebraic expression is the "root" of a few variables. in case you are trying plugging numbers into the variables of your equation it is going to probable develop into clearer.
2016-11-26 20:05:10 · answer #4 · answered by gattus 4 · 0⤊ 0⤋
You also have to take the square root of 8 with the x.
so it'd be about 2.83x
2007-04-21 22:39:00 · answer #5 · answered by mkveliferrari 2 · 0⤊ 0⤋
ne'er!!!!!!!!!
let's say { } is equal 2 square root!
so da answer gonna B {8}x or more simplified its gonna B
2{2}x
2007-04-21 22:41:50 · answer #6 · answered by Anonymous · 0⤊ 0⤋
√(8.x²) = √8.√(x²) = √8.x = √(4x2).x = 2.√2.x
2007-04-21 23:11:40 · answer #7 · answered by Como 7 · 1⤊ 0⤋
No - it is sqrt(8)*x or
2x*sqrt(2)
2007-04-21 22:39:56 · answer #8 · answered by blighmaster 3 · 0⤊ 0⤋
no......its 2x*sqrt(2)
2007-04-21 22:38:43 · answer #9 · answered by bob 3 · 0⤊ 0⤋
+2root2x or -2root2x
2007-04-21 22:55:58 · answer #10 · answered by krienztcruxtz 3 · 0⤊ 0⤋