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2007-04-21 21:17:16 · 5 answers · asked by sarah- 2 in Science & Mathematics Chemistry

5 answers

All molecules have Van der Waals forces between them. Now, SiCl4 is a non-polar substance while PCl3 is a polar substance. When a molecule is polar, it has an additional intermolecular force known as dipole-dipole attraction. Thus PCl3 has a greater force of attraction in between its molecules so it has a greater boiling point than SiCl4.

2007-04-22 00:32:25 · answer #1 · answered by Y L 2 · 0 0

sicl4 boiling point pcl3

2016-02-01 16:15:36 · answer #2 · answered by Diena 4 · 0 0

PCl3 is a polar molecule, and SiCl4 is not. PCl3 therefore has dipole-dipole attractions, and SiCl4 only has weaker vdW forces.

2007-04-21 21:52:43 · answer #3 · answered by Gervald F 7 · 0 0

electrostatic force of attraction is less in sicl4 compared to pcl3

2007-04-21 21:28:53 · answer #4 · answered by pratibha b 1 · 0 0

Si is more electroposite... as electropositivity increases down the group in periodic table. so bond strength is more in SiCl4...

2016-03-18 05:18:44 · answer #5 · answered by Anonymous · 0 0

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