I need help solving a math formula?

Question

Assume W=100
If i have the following formulas:
X2 = (W - Y) + X
Y2 = (W / 2) - ((W - Y) / 2) + (X / 2)

If I know X2=100 and Y2 = 50 how do I solve for X & Y ?

Answer 1

{ w = 100, x = 50, y = 50 }.

i used this site http://wims.unice.fr/wims/en_tool~linear~linsolver.html

i entered this in

100 = (W - Y) + X
50 = (W / 2) - ((W - Y) / 2) + (X / 2)
100 = W

Then I pressed "solve the system"

Answer 2

X2 = (W-Y) + X (Equation 1)
Y2 = (W/2) - (W-Y)/2 + (X/2) (Equation 2)

Assumptions:
W = 100
X2 = 100
Y2 = 50

Just substitute the above values in Equation 1 & 2
X2 = (W -Y) + X (Equation 1)
100 = (100 - Y) + X
100 = 100 - Y + X
100 - 100 = 100 -100 - Y + X
0 = -Y + X (Equation 3)

Y2 = (W/2) - (W-Y)/2 + (X/2)
50 = 100/2 - (100-Y)/2 + X/2
Multiply the equation by 2 to get rid of the denominator
2(50) = 2(100/2) - 2(100-Y)/2 + 2(X/2)
100 = 100 - (100-Y) + X
100 = 100 - 100 + Y + X


100 = Y + X (Equation 4)
Add Equation 3 and 4

0 = - Y + X (Equation 3)
100 = Y + X (Equation 4)
0 + 100 = -Y + X + Y + X
100 = 2X
100/2 = X
50 = X
or X = 50 ====>Value of X
Substitute the value of X to Equation 1
X2 = (W-Y) + X
100 = 100 - Y + 50
100 - 100 - 50 = -Y
-50 = - Y
Multiply by -1
(-1)(-50) = (-1) (-Y)
50 = Y
or Y = 50 ===> Value of Y
To check:
X2 = W-Y + X (Equation 1)
100 = 100 - 50 + 50
100 = 100 (Correct)
Y2 = (W/2) - (W-Y)/2 + X/2
50 = 100/2 - (100-50)/2 + 50/2
50 = 50 -(50/2) + 25
50 = 50 - 25 + 25
50 = 50 (Correct)

Answer 3

I did it a bit differently. If there are fractions first thing I do is get rid of them if I can. I multiplied every term in the second equation by 2.
2(y^2)=2(w/2)-2((w-y)/2)+(x/2)
That left 2y^2=w-(w-y)+x
2y^2=w-w+y+x
y^2=50
2(50)=y+x
y+x=100

I put the numbers for w and x^2 into the first equation.
100=100-y+x
0=-y+x Add y to both sides
y=x
Take the second equation that you turned into y+x=100 and since y=x substitute x in for y:
x+x=100
2x=100
x=50 since y=x, y also equals 50.
I hope that this helps and doesn't seem to confusing.

Answer 4

Sove the equations for x and y:

From the first you have x=x2 - (w - y) .

Put this into the second equation:
y2 = (w/2) - ((w - y) / 2) + [x2 - (w - y)] / 2
PS - The [ ... ] just show where we substituted for x.
Now solve this equation for y.

Put in the values you have for x2, y2, and w to calculate the value of y.
Then you can calculate the value of x.

Hope this helps!

Answer 5

x = X2 - W + y --------------------(1)

Y2 = W/2 - (W/2 - y/2) - x/2
Y2 = W/2 - W/2 + y/2 - x/2
x + y = 2Y2 -----------------------(2)

replace in (2) x found in (1)
X2 - W + y + y = 2Y2
2y = 2Y2 - X2 + W
y = Y - X2/2 + W/2

x = X2 - W + Y2 - X2/2 + W/2 = X2/2 - W/2 + Y2

replacing A B and W by their values we get
x = 100/2 - 100/2 + 50 = 50
y =50 - 100/2 + 100/2 = 50

Answer 6

I assume x2 means x squared, so just take the square root: x would equal 10 and y would equal 7.071.

Answer 7

nl + nm = ok ingredient out an n and get n(l+m)=ok divide the two facets by employing (l+m) and get n=ok/(l+m) get m's on the two facets so r = mnp +m facor out an m so r=m(np+a million) divide the two facets by employing (np+a million) so m=r/(np+a million)