3m^2/2n * n^2/12
2007-04-21 15:25:52 · 4 answers · asked by Lunour 1 in Science & Mathematics ➔ Mathematics
It's hard to tell from the way it is written. Is it:
(3m^2)/2n or is it?
3m^(2/2n) where the exponent is (2/2n).
same for the second part of the equation. Please clarify using parentheses.
2007-04-21 15:36:35 · answer #1 · answered by kelsey 7 · 0⤊ 0⤋
Huh? Dude, chill out, we'll help you, alright? Deep breaths: Breathe in .... breathe out .... breathe in .... breathe out ....
Anyway, what you want to do is factor everything, and then cancel. When you multiply the fractions, you get
(3 m^2 n^2) / (24 n)
Factoring gives you
(3*m*m*n*n) / (2*2*2*3*n)
You can cancel a 3 and an n from the top and bottom, which gives you
(m*m*n) / (2*2*2) = m^2n/8 = 1/8 * m^2n
See, that wasn't so bad, was it? Hang in there, and just stay calm, and work through it. You just need practice. You'll get it.
2007-04-21 22:40:22 · answer #2 · answered by Paul D 3 · 0⤊ 0⤋
Take care of the constants: 3/2 * 1/12 = 1/8 so the expression reduces to
m^2*n^2 / 8*n
Now cancel the n terms
m^2*n / 8
2007-04-21 22:37:02 · answer #3 · answered by gp4rts 7 · 0⤊ 0⤋
(=^-^=)
2007-04-21 22:34:21 · answer #4 · answered by Cowondamoon 2 · 0⤊ 0⤋