(-3x² + 5x + 1) -2(5x² - 2x + 3)
Do I distribute the -2 with (5x² - 2x + 3) and then multiply it all out? or is it subtraction? that -2 is throwing me off. Also, if its multiplication do I multiply EVERY term in the first part the EVERY term in the second? If so then wow that's long. thanks!
2007-04-21 14:18:12 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
with EVERY term in the second part**
thats what I meant.
2007-04-21 14:19:14 · update #1
Right now this is only an expression and not an equation or a problem.
Maybe it is an exercise in simplification.
If so, the the second part needs to all be multiplied by -2 before being combined with the first part.
-2(5x² - 2x + 3) = -10x^2 +4x -6
all together then -3x^2+5x +1 -10x^2 +4x -6
now simplify
-13x^2 + 9x -5
2007-04-21 14:25:03 · answer #1 · answered by ignoramus 7 · 0⤊ 0⤋
(-3x² + 5x + 1) -2(5x² - 2x + 3)
You're quite right: Distribute the -2 with every term in 5x² - 2x + 3, and then simplify. Like this:
(-3x² + 5x + 1) + (-10x² + 4x - 6)
...and here we go, simplifying:
-3x² + 5x + 1 -10x² + 4x - 6
-13x² + 9x - 5
Tada. How fun.
Barjesse37
2007-04-21 14:30:13 · answer #2 · answered by barjesse37 3 · 0⤊ 0⤋
Like you were saying, distribute the -2 to the (5x² - 2x + 3). Then you will have a problem looking like
-3x² + 5x + 1 - 10x² + 4x - 6
Add your like terms, factor and solve! (**I assume this problem is equal to zero)
2007-04-21 14:23:42 · answer #3 · answered by ilovedurango 3 · 0⤊ 0⤋
(-3x² + 5x + 1) -2(5x² - 2x + 3)
-3x² + 5x + 1 -10x² +4x -6
-13x² +9x-5 is your answer
2007-04-21 14:25:35 · answer #4 · answered by Alan 1 · 0⤊ 0⤋