A ball is thrown from the top of a 75-foot tower with a velocity of 32 feet per second?

Question

(a) what is the equation of the parabolic path?
(b)how far does the ball travel horizontally before striking the ground?

can someone please teach me how to do this?
the answers are:
(a): y = -(1/64)x + 75
(b): 69.3

Answer 1

You need to specify a very important item, which way the ball is thrown. If it is thrown horizontally, then your path is given by
y= -16 t^2 and x=32 t. y=0 at the tower top
The path "ends" when the ball hits the ground. This happens when -75 = -16 t^2, or t=2.2 secs appx. From the other equation x= 32 x 2.2 sec= 70 feet appx.

Answer 2

Well, I can't answer it because I don't know the angle by which you threw the ball. For instance, if you held the ball over the edge and shot it straight down, the path would be a vertical line. If you shot it sideways, it would make a different path than if you shot it at a 45 degree angle. Come back with the angle and I'll help.