Ok, here is an analogy.
You are besides a road, and just in front of you are all identical vehicles passing by. You count them: 5 a minute. That is essentially related the amperage, which is a function of the number of charges (in Coulomb, a large number of electrons) passing by in a circuit.
Then you measure how big they are, how much energy they must have. Small cars or big trucks. The power of each vehicle is an analogy to the voltage.
If you have no voltage, i.e. there is no engine, then there can not be any vehicle passing by, therefore the voltage is the driving force of the amperage.
Does this make sense?
2007-04-21 10:27:59
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answer #1
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answered by Vincent G 7
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in particular cases Watts = VA, in particular cases they're distinctive. once you word voltage to a basically resistive load (heater, easy bulb, and so on), then the voltage and cutting-edge are constantly in section. if so the Watts = VA = volts x amps. once you have inductance or capacitance in a circuit, the volts and amps would be out of section so the somewhat skill is Watts = volts x amps x sin(section distinction), while VA continues to be in basic terms volts x amps. In that 2d case Watts < VA.
2016-12-10 08:03:13
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answer #2
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answered by Anonymous
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Like in plumbing, volts are electrical pressure - amps are the size of the pipe. Two completely different things - by the way Amps kill - volts will sometimes throw you away from the circuit.
http://en.wikipedia.org/wiki/Volts
http://en.wikipedia.org/wiki/Ampere
"There is no security in this life. There is only opportunity."
- Gen Douglas MacArthur
2007-04-21 10:25:53
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answer #3
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answered by patrsup 4
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The best I can do is this E=I*R
E= volts or pressure.
I = the current ,that the electrons moving through the wire.
R= Resistance to current flow.
2007-04-21 13:17:32
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answer #4
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answered by JOHNNIE B 7
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ampere is the unit of intensity of th current.
volt is the unit of potential difference or EMF of a battery.
2007-04-21 10:55:13
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answer #5
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answered by Anonymous
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