(t+3)^2-12(t+3)+35=0?

Answer 1

This is equation of degree 2 in t +3. The roots are 2 numbers whose sum is 12 and whose product is 35, that is, 5 and 7.

So, the roots of your equation are the solution of t +3 = 5 and t +3 = 7, that is 2 and 4.

Of course , you could develop your equation to get an equation in t, but this would require much more algebraic work

Answer 2

There's more than one way to do this one. Here's one way,

Let x = t + 3. Then we are looking for the solutions of x^2 - 12x + 35 = 0.

This factors as (x - 7)(x - 5) = 0. So the solutions of the equation are x = 5, x = 7.

Since x = t + 3, this means that t = 2, t = 4 are solutions to the original equation.

Answer 3

t+2 = z

Fin z and then find t

Ilusion