Can anyone express 5logc x+logcy-2logcz as a single logarithm?

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Can anyone express 5logc x+logcy-2logcz as a single logarithm?
That c is below the log (kind of like square root is above a number).

2007-04-21 09:38:56 · 2 answers · asked by TICKLES 1 in Science & Mathematics ➔ Mathematics

logc(x^5*y/z^2)

2007-04-21 09:46:01 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋

logc ((x^5y)/z^2).
That is, x to the 5th power times y, all divided by z squared.

2007-04-21 17:50:15 · answer #2 · answered by jogimo2 3 · 0⤊ 0⤋