2y^2=6-5y how to do this?

Answer 1

First, subtract 6 and 5y to both sides (that is, move the 6 and -5y over to the left side):
2y² + 5y - 6 = 0

Now you just use the quadratic formula. You'll probably have to memorize it at some point:
Ay² + By + C = 0
──► y = [-B ± √(B² - 4AC)] / (2A)

So just apply this to your problem, where:
A = 2
B = 5
C = -6

──► y = [-5 ± √(5² - 4·2·(-6))] / (2·2)
= [-5 ± √(25 + 48)] / 4
= (-5 ± √73) / 4

That's as far as you can go without approximating the answer. If you WANT to approximate the answer, just use a calculator:

√73 ≈ 8.54
──► y ≈ {-0.89, 3.39}

Answer 2

you move all the terms to one side.. so you add the 5y and subtract the 6 and you wil get 2y^2+5y-6=0. Right? then you need to use the quadratic equation becuase you can't factor this equation. if you use quadratic equation, you get -5 plus or minus square root of 73 all over 4. any question, feel free to email me at [e-mail]

Answer 3

2y² + 5y - 6 = 0
x = [- 5 ± √(25 + 48)] / 4
x = [- 5 ± √73 ] / 4
x = 0.886 , x = - 3.396

Answer 4

2y^2 + 5y - 6 = 0
y = {-5 +- sqr[(5)^2 - 4(2)(-6)]}/2(2)
= {-5 +- sqr[25+48]}/4 = {-5 +- sqr[73]}/

Answer 5

2y^2 + 5y - 6 = 0
y = {-5 +- sqr[(5)^2 - 4(2)(-6)]}/2(2)
= {-5 +- sqr[25+48]}/4 = {-5 +- sqr[73]}/4

Answer 6

use the solver on your calculator