How do you write without negative exponents: 3^ -3 a^ -2 b^5 divided by c^ -3 d^ -4?

Answer 1

okay.. if you have negative exponent(s) on the numerator, you move all the exponents to the bottom and if you have negative exponent(s) on the denominator you move all the exponents to the top... so you will have to move 3^-3 to the bottom and a^-2 to the bottom. you will have to move c^-3 and d^-4 to the top. but when you move, the negative on the exponents erase. so your answer should be (b^5) (c^3) (d^4) all over 27 (or 3^3) times a^2. any questions, please feel free to email me at [e-mail]

Answer 2

any number to a negative power is equivlent to 1 over that same number to a possitive number.

so basically you flip the negative ones over

, a^2 goes to the bottom and b^5 stays there at the top

C^3 and d^4 both get moved to the top giving you

(b^5c^3d^4)/27a^2

27 comes from the 3^-3

Answer 3

(2x^-3y^4)^-3 (distribute the exponent) (2)^-3x^9y^-12 (bypass the unfavorable exponents to the denominator to cause them to effectual) x^9/(2^3y^12) x^9/(8y^12) <===answer once you word an exponent to a unique exponent, you multiply the powers, like (x^2)^3 = x^(2*3) = x^6. to regulate a unfavorable exponent to a favorable exponent, you bypass it from the numerator to the denominator or from the denominator to the numerator. And once you stated "in this challenge each and each of the squared 3's are unfavorable," i imagine you meant each and each of the exponents of three are unfavorable, on condition that "sq." potential fairly to the flexibility of two.

Answer 4

3^ -3 a^ -2 b^5 c^ 3 d^ 4
=(1/(27a^2) )* b^5 c^ 3 d^ 4

Answer 5

you make it a fraction for instance 3^-4 is 3^1/4

Answer 6

Its Saturday!

Answer 7

Have a large beer