Log(base 2) 6.8 = x
b^x = y
=>
log(base b) y = x
My teachers always told me "a log is an exponent", so set the exponent (x) equal to the log of the answer (6.8) with the base equal to the base of the exponent(2).
2007-04-21 09:12:34
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answer #1
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answered by eviljebus 3
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well that would be pretty easy.
first thing we need to do is log each side
log(2^x) = log (6.8)
now we can use some log rules to simplify this down
exponents can go to the front giving us
xlog(2) = log(6.8)
Well lets bring the log(6.8) over by subtracting it on each side
xlog(2) - log(6.8) = 0
well in log world subtraction is the same thing as division so using some more log rules we get
x log(2/6.8)
hope that helpped ya out.
If you want to solve for x it would be really easy.
Just go back to xlog(2) = log(6.8) then divide each side by log(2)
or you could do that a=b^x or whatever equation the other people used, they work out to be the same.
2007-04-21 09:14:45
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answer #2
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answered by l0uislegr0s 3
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there is a formula.. the formula is log base of b (x)=y which always means b^y=x okay? so by using the formula.. the base is 2, the exponent is 6.8 (or whatever number or variable is to the right of the equal sign), and the number or varible to the right side of the equation is x right? so you get log base of 2 (6.8)=x. If you have any questions, feel free to email me at mashi_cutie@hotmail.com
2007-04-21 09:13:11
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answer #3
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answered by Anonymous
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there is not any favor for that. Exponential equations are regularly switched over to logarithmic form to discover the unknown. yet in case you insist: a = bc is written logarithmically as loga = logb + logc. the secret to fulfillment is to memorise the formulae.
2016-12-04 10:25:59
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answer #4
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answered by Anonymous
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x=log_2 ( 6.8)
base of the log is 2
2007-04-21 09:10:53
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answer #5
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answered by iyiogrenci 6
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y = a^x
log_a y = x
6.8 = 2^x
log_2 (6.8) = x
2007-04-21 09:10:08
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answer #6
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answered by 7
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x.log 2 = log 6.8
0.693 x = 1.917
x = 1.917 / 0.693
x = 2.766
2007-04-21 09:11:13
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answer #7
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answered by Como 7
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I think x = 1.7, or am I wrong I would like to know the correct answer.
2007-04-21 10:16:07
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answer #8
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answered by Dragon'sFire 6
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