Does anyone know how to express log √(x^4 / yz) in terms of sums and differences of logarithms?
2007-04-21 09:04:19 · 4 answers · asked by Magician 1 in Science & Mathematics ➔ Mathematics
0.5log(x^4)-0.5log(yz). Rule of exponents: division=subtraction, multiplication=addition. Also you can bring the power down infront of the log.
2007-04-21 09:08:19 · answer #1 · answered by voraciousvegetables 2 · 0⤊ 0⤋
log a - log b = log (a/b)
log√( x^4 / yz)
= log ( √(x^4) / √(yz)
= log √(x^4) - log √(yz)
= log x^2 - log√( yz)
= log x^2 - 1/2log(yz)
2007-04-21 09:27:55 · answer #2 · answered by Alyssa 2 · 0⤊ 0⤋
log √(x^4 / yz) =1/2* log(x^4 / yz)
=1/2* ( 4logx-logy-logz)
2007-04-21 09:15:21 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
log a - log b = log (a/b)
log√( x^4 / yz)
= log ( √(x^4) / √(yz)
= log √(x^4) - log √(yz)
= log x^2 - log√( yz)
= log x^2 - 1/2log(yz)
2007-04-21 09:12:57 · answer #4 · answered by 7 · 0⤊ 0⤋