9t^2-t-8=0?

1 ⤊

2007-04-21 08:51:41 · 3 answers · asked by kadayas h 1 in Science & Mathematics ➔ Mathematics

Factor

(t - 1)(9t + 8) = 0

Set each equal to zero and solve

t - 1 = 0

t = 1

9t + 8 = 0

9t = -8

t = -8/9

2007-04-21 09:05:14 · answer #1 · answered by suesysgoddess 6 · 1⤊ 0⤋

(9t+8)(t-1) = 0
so t = -8/9 or +1

2007-04-21 09:05:00 · answer #2 · answered by kellenraid 6 · 0⤊ 0⤋

(9t + 8).(t - 1) = 0
t = - 8/9 , t = 1

2007-04-21 09:38:24 · answer #3 · answered by Como 7 · 0⤊ 0⤋