2007-04-21 08:35:22 · 8 answers · asked by lashawnwuzhea2005 1 in Science & Mathematics ➔ Mathematics
10/x = x - 3
x(10/x) = x(x - 3)
10 = x² - 3x
10 - 10 = x² - 3x - 10
0 = x² - 3x - 10
0 = x² - 5x + 2x - 10
0 = x(x - 5) + 2(x - 5)
0 = (x + 2)(x - 5)
- - - - - - - s-
2007-04-21 09:10:41 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
how would i solve 10/x=x-3?
10/x=x-3 multiply both sides by x
10 = (x-3)x
10 = x^2-3x subtract 10 from both sides
0 = x^2-3x-10 Factor
0 = (x-5)(x+2) Set each term equal to zero and solve.
x-5 = 0 and x+2 = 0
x-5 = 0 Add 5 to both sides
x = 5
x+2 = 0 subtract 2 from both sides
x = -2
x = 5, or x = -2
2007-04-21 15:48:59 · answer #2 · answered by Pam 5 · 0⤊ 0⤋
10= x^2 -3x
0 = x^2-3x-10
0= (x-5)(x+2)
therefore,
0=x+2 0=x-5
two answers assuming no given restricted domain
x=-2 or x = 5
2007-04-21 15:44:13 · answer #3 · answered by T.B. 2 · 0⤊ 1⤋
multipy both sides by x
10 = x^2 - 3x
subtract 10 from both sides
x^2 - 3x - 10 = 0
use the quadratic formula
(3+-sqrt(49))/2 = (3+-7)/2 = 5 or -2
x = 5 or -2
2007-04-21 15:37:34 · answer #4 · answered by Anonymous · 2⤊ 1⤋
10 = x² - 3x
x² - 3x - 10 = 0
(x - 5).(x + 2) = 0
x = 5, x = - 2
2007-04-21 15:38:57 · answer #5 · answered by Como 7 · 2⤊ 1⤋
10 / x = x - 3
10 = x^2 - 3x
x^2 - 3x - 10 = 0
(x - 5)(x + 2) = 0
x = {-2, 5}
2007-04-21 15:37:49 · answer #6 · answered by Bhajun Singh 4 · 2⤊ 1⤋
10/5=2
5-3=2
x=5
2007-04-21 15:41:53 · answer #7 · answered by ~LOZ~ 6 · 0⤊ 4⤋
x^2-3x-10=0
(x-5)(x+2)=0
x1=5
x2=-2
2007-04-21 15:40:12 · answer #8 · answered by iyiogrenci 6 · 1⤊ 1⤋