Maths puzzle?

Question

How do i work out what B is ?

A = B / B + C

many thanks

Answer 1

If you mean A = B/B + C
Then B is indeterminate (Anything DIVIDED by Itself = ONE)

But if you mean A = {B/(B+C)}

Then we have to collect terms

A (B + C) = B

Expand LHS

AB + AC = B

Collect Terms

AC = B - AB

Factorise RHS

AC = B(1 - A)

Isolating B on LHS

B = {AC/(1 - A)}

Answer 2

I am assuming you mean A = B / [B + C]

Multiply

AB + AC = B

Move all terms with B to one side

AC = B - AB

Factor out the B

AC = B [1 - A]

Divide

AC/[1 - A] = B

Answer 3

A = B / B + C
If you mean this as this is written the answer would be false, so no solution.

But if you mean A = B / (B + C)


A = B/(B+C) multiply both sides by (B+C)
A(B+C) = B
AB + AC = B
AB - B = - AC
B(A-1) = - AC
B = - AC/(A-1)

Answer 4

Assuming you did not write it wrong.
B/B = 1 for any number except 0. Because 0/0 is undefined.
So you have
A = 1 - C
and B is any number except 0
Otherwise what the others said.

Answer 5

no B value.

because B/B=1

Answer 6

If you mean A = B/(B+C)

Then B = (A*C)/(1-A)

Answer 7

I assume that should be:

A = B / (B+C)

In which case:

A(B+C) = B

AB + AC = B

B(A-1) = -AC

B = AC / (1-A)

Answer 8

a =b/(b+c)
ab +ac = b
ab- b = -ac
b(a-1) = -ac
b = -ac/(a-1)

Answer 9

A=C... Right?