MATH Help please!!!!?

Question

What will be the date (month, day, year) and time (hour, minute, second), 1 billion seconds from noon today?

Answer 1

1e9 secs = 11574.07 days

Over the next 31 years, there will be 8 leap years.
So total days over exactly 31 years will be
31*365 + 8 = 11323 to April 21, 2038 at noon.

There are still 251.07 days left to make up the rest.
The 251 days will take us to December 28, 2038 at noon.

Now there are still .07 days = 1.78 hours
= 1 h 46 m 40 sec
It will be 1:46:40 pm on Dec 28, 2038

If this question was given to you 3 days ago, the answer would be Christmas Day.

Answer 2

12 noon today is the set time for April 21st


60 seconds=1 minute
1,000,000,000/60=16,666,667 minutes
60 minutes - 1hour
16,666,667/60=277777.78 hours
24 hours =1 day
277777.78/24=11,574.07 days
365 days to a year
11,574.07/365=31.7097 years
.7097 x 365=259.04 days
31 years from now (noon) April 21, 2038 +259 days=01/05/2039
Considering April 21 st is the 111th day of the year, therefore 111+259=370 We go to a new year January 5,2039-8leap days=December 28,2038

..04 x 24=.96 hours
.96 hours x 60=57.6 minutes
.6minutes x60=36 seconds

My answer is approximately December 28,2038 at 12:57:36pm

Answer 3

First, let's break it down step by step.

It might be less intimidating to go from seconds to minutes to hours to days to months to years.

So, to find out the amount of minutes, divide the number of seconds (10^9) by 60. Take the remainder and set it aside - this is the number of left-over seconds.

Then, take the number of whole minutes (round down) and divide it by 60 to get hours. Again, take the remainder - that'll be the left-over minutes.

Repeat until you get years, months, days, hours, minutes, and seconds. Then, add them to the current time and adjust as needed (eg. 93min means add 1hr, subtract 60 min).