x^2-10x-11=0?

Answer 1

find 2 numbers that when multiplied equal -11 and when added equal -10. well the 11 you have no choice but 1 and 11 so add them to make - 10 and it is -11 and 1 so your answer shall be

(x-11)(x+1)

Answer 2

(x-10)(x+1) would be --> "using distributive property" multiplying the 1st terms on both parenthesis x *x = x^2, 1st term(1st parenthesis) to 2nd term(2nd parenthesis) x * +1 = +1x, multiplying the 2nd term(1st parenthesis) and the 1st term(2nd parenthesis) -10 * x = -10x, multiplying the last terms on both parenthesis -10 *+1= -10. in an equation that would be x^2+1x-10x-10 = 0, adding common terms, the next equation would be x^2 -9x -10 = 0 which is wrong. the correct answer would be (x-11) (x+1). i got it using a "short cut" by getting the multiple factors of the last term on the equation(-11) which is obviously just 1 and 11, then put 2 parenthesis with both x as their 1st terms with a positive and negative sign (x-_) (x+_). now the next thing to do is think of a way to get the 2nd term in the equation which is -10x by adding them up. so obviously since its negative the bigger number should be negative in the multiple factors of 11 which is also 11, then put the smaller multiple factors of 11 which is 1 in the positive sign. so when you distribute them the common terms in the middle would be -11x and +1x by adding them you would get -10x. i think this is called a binomial factoring in algebra.

Answer 3

X^2-10X=11
X^2-10X/X=11/X
X-10=11/X
X=11/X+10
X=Square root of 21?

Answer 4

find any two numbers that multiply together to equal -11, and that also add up to equal -10.

that's called factoring.

so, the only two numbers that multiply to equal -11 and add up to equal -10 is
-11, 1

then, you set them both in parenthesis like this...
(x-11)(x+1)=0
use FOIL (multiply the FIRST terms, then OUTER, INNER, and LAST) to check your work...
so it ends up being: x^2+1x-11x-11=0
simplify: x^2-10x-11=0

then, that being correct, then solve.
(x-11)(x+1)=0

set both parenthesis things to zero...
x-11=0
x=11
AND
x+1=0
x=-1

so your answers are x=11 and x=-1

Answer 5

you need to do the quadratic equation for this

x = -1
x = 11

Answer 6

Heather was close, but...
(x-11)*(x+1)
is the answer

Answer 7

(x+11)(x-1)=0
x1=-11
x2=1


or


use a quadratic formula
a=1
b=-10
c=-11

x1=11
x2= -1

Answer 8

(x+1)(x-11)=0

x=-1or 11