domain and range of this function?

Question

i need help finding the domain and range of √3x+6

i'm having difficulties with this so if anyone can help that would be very much appreciated :)

Answer 1

OK, the domain of a function is the values which x can have and still give you a valid number for y (which is the range). So in this case, x has to be zero or greater since the square root of a negative number isn't on the real number line (but it does have an answer--save that for another time!). With x>=0, the value of y has to be 6 or greater. So the domain of the functioin ix x>=0, and the range is y>=6.

Oops, I just read the other answer that was given. I can't tell if the square root sign is over the "x" or not. If it is, then what I wrote above is right. If not, then you follow the same principle, but in this case since x can be any number (if it's not under the square root sign), y can be any number also, it will just be a bit bigger than x.

Answer 2

well for both the range and domain as long as it doesn't equal to negative under the radical you are fine. and for a square root function the range (y values) never go below 0 anyway.

so range is (0, infinity)

to find the domain set 3x+6=0; 3x=-6 x=-2. -2 is the lowest x value that it can be to not be negative under the radical so your domain values are

domain (-2, infinity)

Answer 3

area is how far the equation can stretch around the x-axis selection is how far the equation can stretch around the y-axis A function is an equation that has all genuine solutions. as a result definite, it is a function. The area and selection are all genuine numbers.

Answer 4

domain
3x+6>=0

x>= - 2

range
√3x+6 >=sqrt(6)