write the equation in general form...?

Question

of a line with the same x intercept as 9x-2y+18=0 and through the point (4,-5)?
steps please?

Answer 1

The x intercept of 9x-2y+18=0
is where y is 0.
y = 4,5x + 9
0 = 4,5x + 9
x = -2

So, you'd need a line that goes through (-2;0) and (4;-5)

It would be
y = - 5/6 x - 5/3
or
5/6 x + y + 5/3 = 0

Answer 2

The x-intercept of 9x-2y+18 = 0 is found by setting y=0 and solving for x. Thus x = 2. The x-intercept is (0,2).

The line must pass through (0,2) and (4,-5).
So its slope is (-5-2)/(4-0) = -7/4
Thus equation is y = -7x/4+b, where b is y-intercept.
So 0 = -7(2)/4 +b --> b = 7/2
So y= -7x/4 +7/2
So 4y = -7x +14
7x+4y =14

Answer 3

9x-2y+18=0

When y=0, 9x-(2)(0) +18 = 0 gives x=-2.
This is the point (-2,0).

The line going through (4,-5) and (-2,0) has slope = (-5 -0)/(4 - -2) = -5/6.

y-y1=m(x-x1) gives
y-0 = (-5/6)(x - -2)
y = (-5/6)x -5/3