the natural log of x raised to 6
2007-04-21 05:47:18 · 7 answers · asked by packerswes4 5 in Science & Mathematics ➔ Mathematics
Just use a combination of the chain rule, power rule and differential of ln.
(6/x)*(ln x)^5
If you want to convince yourself of this then use substitution
u = ln x.
2007-04-21 05:50:52 · answer #1 · answered by Anonymous · 0⤊ 0⤋
derivative of y=ln[(x-5)/(x-6)] at x=7.? 1/(-30 + 11 x - x^2) at x = 7 -1/2
2016-05-20 03:31:17 · answer #2 · answered by ? 3 · 0⤊ 0⤋
If you are asking me the derivative of {log x} raised to the power of 6, it is 6 times {log x} raised to the power of 5 divided by x. If you want that of [log{x raised to the power of 6}] it is 6 divided by x.
2007-04-21 05:56:06 · answer #3 · answered by shreyas 1 · 0⤊ 0⤋
6(ln x)^5 *1/x
2007-04-21 05:56:35 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
[ (ln x )^6]' =
6(lnx)^5*(lnx)' =
6(ln(x))^5*(1/x)=
[6(lnx)^5/x]
2007-04-21 06:00:53 · answer #5 · answered by Anonymous · 0⤊ 0⤋
y = (lnx)^6
let u = lnx
du/dx = 1/x
y = u^6
dy/du = 6u^5
dy/dx = dy/du * du/dx
= (6/x)*(lnx)^5
2007-04-21 05:51:41 · answer #6 · answered by Dr D 7 · 0⤊ 0⤋
17. Trust me. Write it on your assignment paper in pen. Got any more?
2007-04-21 05:50:59 · answer #7 · answered by Ashley Oasis 3 · 0⤊ 3⤋