8x^2(ln7x)
2007-04-21 05:35:23 · 4 answers · asked by packerswes4 5 in Science & Mathematics ➔ Mathematics
Use the product rule:
d/dx (8x² ln 7x) = 8x² * d/dx ln 7x + ln 7x * d/dx 8x²
=
8x²/7x + 16x ln 7x
=
8x/7 + 16x ln 7x
2007-04-21 05:46:17 · answer #1 · answered by Anonymous · 0⤊ 0⤋
16x(ln7x) +7* 1/(7x)(8x^2) <-- product rule
=16xln7x+ 8x
2007-04-21 05:53:15 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
[(2 ln7x) + (14 ln x )] * 8x^2(ln7x)
2007-04-21 06:12:30 · answer #3 · answered by Anonymous · 0⤊ 0⤋
leave 6 out first. considering x^4/1-x write x^4= x^3*x, so that we can write the expression as x^3(x+1-1)/1-x. separate it out like x^3(x-1)/1-x+x^3/1-x, this results in (-x^3)+(x^3/1-x) since the highest power of this expression is 3 and you need to find the fourth derivative so all will be zero.
2016-05-20 03:28:33 · answer #4 · answered by ? 3 · 0⤊ 0⤋