factoring
2007-04-21 03:50:04 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(3x+2)(x+5)
2007-04-21 05:56:30 · answer #1 · answered by Anonymous · 4⤊ 0⤋
3x² + 17x + 10
The middle term is + 17x
Find the sum of the middle term
Multiply the first term 3 times the last term 10 equals 30 and factor
Factors of 30 =
1 x 30
2 x 15. . .<=. .use these factors
3 x 10
5 x 6
+ 15 and + 2 satisfy the sum of the middle term
insert + 15x + 2x into the equation
3x² + 17x + 10
Factor by grouping
3x² + 15x + 2x + 10
3x(x + 5) + 2(x + 5)
(3x + 2)(x + 5)
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2007-04-21 04:05:45 · answer #2 · answered by SAMUEL D 7 · 1⤊ 0⤋
3x^2+17x+10=0
(3x + 2) (x + 5) = 0
2007-04-21 03:53:38 · answer #3 · answered by millet_0220 4 · 1⤊ 0⤋
3x^2+17x+10
=3x^2 + 15x +2x +10
=3x(x+5) + 2(x+5)
=(x+5)(3x+2)
2007-04-21 04:22:10 · answer #4 · answered by san 3 · 1⤊ 0⤋
Okay. ax^2+bx+c factors as follows:
(mx+g)(nx+h)
a=mn
c=gh
b=mh+ng
so mn=3, gh=10, and mh+ng=17
10 breaks down to 1 and 10 or 2 and 5. 3 breaks to 1 and 3. so the only way to reach 17 is 3*5+1*2
(3x+2)(x+5)
2007-04-21 03:56:24 · answer #5 · answered by apachetear 2 · 1⤊ 0⤋
(3x + 2)(x + 5)=0
3x + 2=0
x= -2/3
x + 5=0
x= -5
x = -2/3 or -5
2007-04-21 04:07:07 · answer #6 · answered by Anonymous · 1⤊ 0⤋
(3x+5)(x+2)
2007-04-21 04:18:35 · answer #7 · answered by Khool 2 · 1⤊ 0⤋
(3x+2)(x+5)
2007-04-21 04:11:42 · answer #8 · answered by watchful 2 · 1⤊ 0⤋
(3x+2)(x+5)
2007-04-21 03:53:31 · answer #9 · answered by dzhang1212 1 · 1⤊ 0⤋
(3x+2)(x+5)=0
x=-2/3 or -5
2007-04-21 03:54:05 · answer #10 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋