A sign is suspended by two wires. Wire 1 makes an angle of 43.0° with the roof, and wire 2 makes an angle of 55.0° with the roof. The sign has mass 42.8 kg. Find the tension in wire 2 in N.
I already know the answer for this which is 310N but I can't figure out how to actually get this - please help
2007-04-19 23:40:09 · 2 answers · asked by Minty 1 in Science & Mathematics ➔ Physics
Break the tension in the wires into their vertical and horizontal components:
T1x=T1*sin43, T1y=T1*cos43
T2x=T2*sin55, T2y=T2*cos55
Sum the different components:
T1x=T2x
T1y+T2y=42.8 * 9.8=419.9N
Use the horizontal component equation to put T1 into terms of T2 and replace that in the vertical component equation and solve your way out.
T1*sin43=T2*sin55 (or, T1=1.201*T2)
Replace T1 with 1.201*T2 in the vertical equation and solve your way out.
2007-04-20 00:04:16 · answer #1 · answered by lango77 3 · 0⤊ 0⤋
as in step with your determine, if T1 is the stress in horizontal cable and T2 is the stress in the different cable, then in equilibrium, we could desire to continually have T2 sin 30 = weight of ball a hundred and fifty , then T2 = a hundred and fifty/sin30 = 3 hundred N now, T1 = T2 cos 30 = 3 hundred x 0.866 = 259.8 N = 260 N (almost) so,your answer could desire to be D
2016-11-26 00:02:52 · answer #2 · answered by Anonymous · 0⤊ 0⤋