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2007-04-19 23:08:39 · 4 answers · asked by hellokid 1 in Science & Mathematics Mathematics

4 answers

r=2sin2&theta

r = 4sin&theta·cos&theta

multiply both sides by r²
then use: y=r·sin&theta, x = r·cos&theta, r = √(x²+y²)

r³=4·r·sin&theta·r·cos&theta

√(x²+y²)³ = 4xy

2007-04-19 23:12:07 · answer #1 · answered by M 6 · 5 0

x = r cos theta = 2 sin 2 theta cos theta
y = r sin theta = 2 sin 2thete sin theta

2007-04-19 23:20:02 · answer #2 · answered by Mein Hoon Na 7 · 0 0

If this is length 2 at angle 2Ø, then:-
Components are 2 cos 2Ø and 2 sin2 Ø
Can`t find theta so used Ø!!

2007-04-19 23:49:58 · answer #3 · answered by Como 7 · 0 1

y=r sin (theta) -->sin (theta)=y/r
Given r=2 (sin (theta))^2
r=2 (y/r)^2 =2(y^2)/(r^2)
r^3=2y^2
--> y^2=(r^3)/2

2007-04-19 23:38:21 · answer #4 · answered by SweetSagi 2 · 0 1

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