The process of completing a square is as follows:
1) Rearrange so that you have x² + ax = b
2) This needs to be of the form (x + c)².
Multiplying this out gives x² + 2cx + c². Since the x coefficient is both a and 2c, c must be a/2
You also get an extra unwanted c², so you need to take this off (or add it to the other side) to compensate.
3) (x + (a/2))² = b + (a/2)²
4) Plug in your figures
(x + (4/2))² = 6 + (4/2)²
(x + 2)² = 6 + 2²
(x + 2)² = 10
x + 2 = ±√10
x = -2 ± √10
2007-04-19 23:39:54
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answer #1
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answered by Tom :: Athier than Thou 6
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If you're want to solve the x^2+4x=6 by completing the square, it could be like this :
x^2 + 4x = 6
x^2 + 4x - 6 = 0
x^2 + 4x + 4 -10 = 0
(x+2)^2 = 10
Take a square root at 2 sides (Left Hand Side and Right Hand Side),
x+2 = √10 --> x = (√10) - 2
or
x+2 = - (√10) --> x = - [ 2 + (√10)]
So, the answer is x = (√10) - 2, or - [ 2 + (√10)]
2007-04-19 22:24:39
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answer #2
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answered by wangsacl 4
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x^2 + 4x = 6
x^2 + 4x + 4 = 6 + 4
(x + 2)^2 = 10
x + 2 = ± √10
x = - 2 - √10, - 2 + √10
2007-04-19 23:10:03
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answer #3
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answered by Helmut 7
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x² + 4x + 4 = 10
x² + 4x - 6 = 0
This is equation that leads to solution by using the quadratic formula.
x = [- 4 ± √(16 + 24)] / 2
x = [- 4 ± √(40)] / 2
x = [- 4 ± 2√(10)] / 2
x = - 2 ± √(10)
2007-04-19 22:23:09
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answer #4
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answered by Como 7
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first of all to the asker, what's x2? Is it (x*2) or (x²)? It appears like as though the asker needs incorrect inquiries to be replied. purely as quickly as I went by using a number of the subject concerns, i'd desire to confirm that it became x² and not 2x. to no longer be impolite, yet I purely basically stated. by the way, for the respond: x²-8x=24, So: x²-5x-24=0. made of two numbers is -24. Sum of two numbers is -5. So the numbers are -8, 3. x²-5x-24=0, for that reason may be written as: x²+3x-8x-24=0, which may be written as: x(x+3)-8(x+3)=0, which provides: (x-8)(x+3).
2016-12-16 10:48:30
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answer #5
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answered by deibert 4
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Huh?
2007-04-19 22:13:29
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answer #6
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answered by Mark 6
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