2007-04-19 21:58:52 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x1=(1+sqrt33)/4
x2=(1-sqrt33)/4
2007-04-19 22:05:22 · answer #1 · answered by UNborn g 1 · 0⤊ 0⤋
2x^2 - x - 4 = 0
Using Quadratic Formula:
x = (-b + or - sqrt( b^2 - 4ac)) / 2a
x = (1 + or - sqrt(1-4*2*-4)) / 4
x = (1 + or - sqrt(33))/4
Time to reach for a calculator
x = 1.6861406625
or
x = -1.1861406625
2007-04-19 22:07:52 · answer #2 · answered by Nick Solly 2 · 0⤊ 0⤋
Try the quadratic formula.
2007-04-19 22:06:11 · answer #3 · answered by Mark 6 · 0⤊ 0⤋
1+√(1-4(2)(-4)) =m
1-√(1-4(2)(-4)) =n
answer:m/2(2) & n/2(2)
2007-04-19 23:17:57 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Use quadratic formula
2007-04-19 22:07:16 · answer #5 · answered by Tasm 6 · 0⤊ 0⤋
x = [1 ± √(1 + 32)] / 4
x = [1 ± √(33)] / 4
x = 1.69 , x = - 1.19
2007-04-19 22:15:11 · answer #6 · answered by Como 7 · 0⤊ 0⤋
the roots are
(1+/- (1+32)^0.5)/4
one root is 1.64 the other 1.18
2007-04-19 22:08:22 · answer #7 · answered by maussy 7 · 0⤊ 0⤋
x=1.6861,-1.1861
2007-04-19 22:03:44 · answer #8 · answered by Rocking Ranjit 2 · 0⤊ 0⤋