How do I find the antiderivative of 23.95e(to the power of .06t) t has value of 80 and 0?

Question

The answer is 395.88, I don't know how to get it. In the question there is a line with 80 at the top of it and 0 at the bottom. I think those are the value of t, but Im not sure.

Answer 1

80
∫ 23.95e^0.06t =
0

(23.95/0.06)e^0.06t from 0 to 80 =
399.1667(e^4.8 - e^0) = 48,103.74
but if 0.06 is - 0.06 the answer is
- 399.1667(e^-4.8 - e^0) = 395.8816